Help figure out ratios
You've got some'thin screwed up because 1st should have the greatest difference number of tooth count from one to the other. . Fourth gear is a straight through coupling, unless it's an OD (impossible, I think? on an 18 spline) in which case 3rd on the shifter, but really the same gear, is coupled.
So mathematically, all you do is divide one tooth count by the other, so your numbers are
1st is 1.5:1
2nd is 1.05:1
3rd is 1.33:1
4th is 1.66:1
So something is seriously wrong with "how" you counted. You have to figure the input shaft mating the cluster----how many teeth are those two?
And then figure that with the ratio of the other gears. But there IS NO tooth count for 4th, so I have no idea what it is that you are actually counting.
Here's a diagram:
Look at part labeled 31 and 51. You have to count those two mating gear teeth. That is, the largest gear on the front of the cluster
Then starting at the REAR of the cluster (part label 51) You have in order 1st, the reverse is the only "straight cut", then 2nd, then 3rd. So you have to count those teeth and the gears which mesh with them on the main shaft. Notice how the gears get larger from rear to front---the cluster will be spinning a lower (numeric) ratio, higher speed, with each gear.
So that's the part labeled
18--1st gear
9--2nd gear
42--3rd gear
You've got some'thin screwed up because 1st should have the greatest difference number of tooth count from one to the other. . Fourth gear is a straight through coupling, unless it's an OD (impossible, I think? on an 18 spline) in which case 3rd on the shifter, but really the same gear, is coupled.
So mathematically, all you do is divide one tooth count by the other, so your numbers are
1st is 1.5:1
2nd is 1.05:1
3rd is 1.33:1
4th is 1.66:1
So something is seriously wrong with "how" you counted. You have to figure the input shaft mating the cluster----how many teeth are those two?
And then figure that with the ratio of the other gears. But there IS NO tooth count for 4th, so I have no idea what it is that you are actually counting.
Here's a diagram:
Look at part labeled 31 and 51. You have to count those two mating gear teeth. That is, the largest gear on the front of the cluster
Then starting at the REAR of the cluster (part label 51) You have in order 1st, the reverse is the only "straight cut", then 2nd, then 3rd. So you have to count those teeth and the gears which mesh with them on the main shaft. Notice how the gears get larger from rear to front---the cluster will be spinning a lower (numeric) ratio, higher speed, with each gear.
So that's the part labeled
18--1st gear
9--2nd gear
42--3rd gear
