180 or 190 thermostat?

Okay, I'm gonna be honest, this is really started to annoy me. Lets get this straight. First off, if you are going to start spouting physics equations at me, at least get them correct. If you actually knew anything about physics, you would know that heat transfer is a incorrect statement. Heat=transfer of energy. You are basically saying transfer energy transfer. Second, C is not a constant by any means, it is material specific. Third of all, that equation is wrong, that process only accounts for one material, where you would need two specific heat variables. Also, to use delta T, you need two comparison points. Obviously you are missing two parts of the equation. The equation are using can only tell you what the coolant is capable of, not the system. What you want is the Carnot Heat Engine efficiency equation, which you could use to derive and find the variable Q's. Fourth, your localized pressure would only be present, wait for it, at the t-stat. Six degrees of higher boiling point at the t-stat is completely immaterial. If i have a gauge with a sensor right next to the t-stat that says 190* F and plain water (NOT EVEN WITH ETHYLENE GLYCOL IN IT) boils at 212*, why does six degrees matter And do you wanna know why I can say all this? Because I have taken a thermodynamics course, I have taken a mechanics physics course, I have taken a modern physics course and many more... its the perk of having a major in physics.