Anybody really good at math?

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a line at an angle of 4.1 degrees is what you described

but a 7in line tangent to a circle resulting in a 1/2 in gap between the endpoint and the circle then you have

a raduis of 49.25 inches
 
4.1? So that that works out to a 43.90" circle? Oh, 49.25. I did something a bit off but I got it. Thanks Buckshotbishop. Now If I can just figure out where the other 180 degrees went. (long story)
 
I get 48.75

r^2 +49=(r + 1/2)^2
r^2 + 49=r^2 + r + .25
49=r + .25
r=48.75
 
Is the formula the same when using a Reiman sphere within a Schwartchild phase space?
 
The importance of this had to do with the curvature of the rear quarter panel of a 70 duster. A piece I was looking at using has a 39" circumference. I needed to convert the known rise and fall that I had from my quarter panel to see how far out of register I'd be. Thanks for the input both sides of the Darwinian bridge.
 
Blind Squirrel said:
The importance of this had to do with the curvature of the rear quarter panel of a 70 duster. A piece I was looking at using has a 39" circumference. I needed to convert the known rise and fall that I had from my quarter panel to see how far out of register I'd be. Thanks for the input both sides of the Darwinian bridge.
Click to expand...

So are you insinuating that just because some of us didn't know how to do this kind of math, that we are somehow inferior on an evolutionary scale?
 
why don't you just do what everybody else does and google it?
 
Einstein's famous equation E = mc2, the energy E of a physical system is numerically equal to the product of its mass m and the speed of light c squared. It is customary to refer to this result as “the equivalence of mass and energy,” or simply “mass-energy equivalence,” because one can choose units in which c = 1, and hence E = m.

By the way...... there is no such thing as a line.
Lines are nothing but quantum sectors of weight.
A circle is made up of lines.

You can't get from one point to another without a sectors ( which we all, perceive as a line).

But.. I only stayed in a holiday Inn Express last night...
So I still really can't give a correct answer.

At least I tried....LOL
 
Blind Squirrel said:
So if you have a 1/2" fall every 7 inches. How big is the circle?
Click to expand...
That is a trick question. You described a line that dropped 0.5 inches for every 7 inches. That simply describes a line, not a circle. If you had mentioned that a line intersected a circle, or given some other circle related clue, one could determine the size of the circle. A line that drops 0.5 inches for every 7 inches of run is simply a line with a slope of -0.07143 using the slope formula of (Change in Y) / (Change in X). In this case that is -0.5/7.
 
My uncle (super cool) was a lead die maker at Sterling Stamping plant in the 60's thru the 70's and has just the coolest stories of making all the cool stuff Chrysler did back in the day...he may know :)
 
The Fried Potatoes will be Ready in 20 Minutes.
 
No, the question is valid,only one radius deviates .5" per 7" and the math to
find that can be done.However,it is useless, because it assumes the -0- point of the 7" dim.
extended tangentially from the edge (at a right angle to the radius) out to where the .5" dim.
was observed. We have no way of knowing that,and it's difficult to actually tell in attempting
to take such a measurement. Not to mention it is doubtful the radius is constant, unless the
area in question is relatively small.
Take a strip of metal and form it to the area in question 'til it's rite, then take it
to your prospective donor piece and compare,no math shortcuts you!!! Now get busy!!
:):)
 
It all depends on the ambient air temperature, and the surface temperature of the object in question at the time of measurement.
 
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