Engine required GPH

That's right. You calculated the fuel requirement in pounds per horsepower per hour and converted it to gph.So the requirement is for WOT.
Now the pump rating is usually stated as output at a certain pressure. But when the pump runs without a restriction, it usually puts out a bit more.
Sooo, if you were to run the engine at max output for a long enough period of time, that the floats drop far enough that the only restriction is the wide-open float valves, AND you ran no pressure regulator nor a return system,then the pump might put out more gph. Only a flowtest will prove that.
But heres the thing you gotta know;
At 27.5 gph, thats 1 ounce per second. I think there's probably 50 to 60cc of fuel in a standard Holley bowl. At 7cc per ounce, thats over 7 ounces per bowl so total is 14 ounces. Quick question if your fuel pump quits when the tree turns green, will your car make it to the finish line on 14 ounces? Well at 27.5gph, the math says you have 330hp so about a high 13 second car.So,Ima guessing yes.With a second to spare.
I wouldn't try it tho, heehee
And I'll tell you why; cuz not all of those 14 ounces are coming out at full gallop.

But at 25gph, your pump is putting out 91% of the calculated requirement. And at every shift the rpm drops , and so does the engine output, and so does the pump output requirement.So it has lots of time between shifts to catch up.
Now I made one assumption in all this; that you are asking about an electric pump.
Thank you very much! This is some great information! It is a mechanical setup, but if I understand correctly the main factor with that is that at higher rpms that it can fail to pump as efficiently.