440 source flywheel on LA360... weight question

It can be a bit off and be hard to feel. I'd wait for the answer.... or figure it out this way:

OP, if you look at the diagrams online for the 360 flywheel drilling
(like here: Viewing a thread - 1976 360 flywheel
you can find ones that give a number of 19.79 in-oz at the bottom of the diagram. This number is what is called the 'moment' of the imbalance; 19.79 in-oz the is the standard 'moment' for the 360 flywheel imbalance.

To figure this out on your flywheel:
1. Weigh your weight and 2 screws as precisely as you can (and convert to ounces if you have a gram scale).
2. Then precisely measure the distance from the exact center of the flywheel to the center of the screw holes for both sets of holes. (Try to measure within a 64th of an inch.)
3. Multiply the weight in ounces from step 1 by the distance in inches from step 2; whichever distance from step 2 gives the result that is closest to 19.79 is the hole set you want to use. It really is that simple. (Feel free to post your measurements back here for a doublecheck...)

And as a check, also look at those balance diagrams to verify the location of the weight. Referencing the bolt pattern on the flywheel hub, the weight should be on a line exactly OPPOSITE to the centermost of the 3 drilled holes shown on those drilling diagrams. Be careful to keep track of the pattern relative to the side from which you are viewing the flywheel (engine or clutch side); the diagram in the above link is from the engine side.