Following along here trying to learn, but wouldnt you take 1/2 of the dimension of 0.3125"= 0.15625 ? My thinking is the cup only "holds/houses" 1/2 the "ball" on the rocker?
When you measure length with the 5/16" ball, you subtract the full .3125" from the length measurement (of pushrod + test ball) to get the effective length. The effective length is from the tip of the ball to the BOTTOM of the cup.
