Charging circuit - reduced load on ammeter circuit

Sure.
Given:

Then

Because this

The ammeter won't see any flow along the new, hefty, wire.
If the wire direct from the alternator the battery is hefty, electricity for recharging the battery will take that path.
So what does that mean?

The ammeter only works when electricity flows through it. The electomagnetic field created by the electricity flowing through the meter deflects the needle.
Why would there be any current through the meter if there is a shorter path to the battery?

It still should show discharge.
Why?

Where does the electricity wants to go?
And what's the shortest path there?
Is it all the way across the engine bay to the alternator, and then from the alternator all the way to the main splice?

Probably not.
Bottom line will come down to which route has the least resistance.

@Mopar Tim did a wire around on his '66 and this what he observed.
Yeah. You seem to not understand you're tellin me everything HERE that I already know. The big wire....while it reduces current to the ammeter, does not stop it altogether. So it will still "do something". It will still register "something" although at a reduced capacity. It will now have a "new" operating range.

My question is how do you know for 100% sure that I cannot get used to this new operating range and gauge what the system is doing accordingly? From what I am gathering, you're simply telling me the same thing over and over that I already know and are not answering my question. Have you not actually tried it?