Ballast resistor wiring

View attachment 1716414044
J2 is the original ignition circuit.
J2B is the original segment going to the coil from the .6 ohm ballast.

Oddly we do not see the J2A tied into J2.
Someone may have cut and moved it, or could this be a '69 model year?
In '69 wire J2 goes to the voltage regulator first, and J2A connects from the regulator to the ballaast reisistor.

Also by '69 the neutral safety is combined with the back up light switch in the automatic transmissions.
Yes I have the 69 diagram, so I had been trying to translate that to how the ECM was incorporated.
So in my photo would you be saying that J2B and J3 are joined in the connector and still effectively running from the ignition switch to the coil and are still an active part of the start ignition circuit, with power coming from J1 via either R6 or A1A?
And then J2 / J2a (as its a 69 model) is bringing power to the 4 pin resistor and feeding the coil via the red wire labelled coil in my photo? The pale blue wire from the ECM in your illustration corresponds to my dotted yellow wire connecting to J2 but what do you think is the reason for the dotted green wire and also the red wire I marked with a question mark?
Looking at the coil it has 2 wires in to positive - the pinkish wire from the 4 pin resistor that I labelled Coil and another red wire, perhaps this is a continuation of J2B / J3? It's my only explaination, they disappear into a mess ofwires in electrical tape and the red wire comes out of it further along.
The black and yellow wire to the negative on the coil I think does run to the top pin on the ECU as shown in your diagram, there is a second wire (red) from the negative on the coil which I believe might have been to an aftermarket tachometer.

Just saw your little arrow and ? on my photo next to the yellow and black wire, I think this is the wire that goes from the top pin on the ECM cap and runs to the negative on the coil.
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