Sorry this is not true. At least not as you explained it. One side of the resistor supplies the COIL and the other side supplies the ECU. THAT is the half that was deleted. The coil side has never changed so far as the circuit. IN FACT if the ECU goes bad, you can pull the ECU connector, drop in an old points distributor, hook the dist. to the coil NEG and if the ECU was the only problem, it will run
When you START the car with a 4 terminal ballast, "things are a trick." There is no "ignition run" power during start, the coil PLUS is powered through the ballast bypass (brown, IGN2) circuit. So the power BACKFEEDS through the resistor to power the ECU during crank. VERY POOR DESIGN in my opinion
Here is the circuit. The "ignition run" at lower right is DEAD during cranking. Only power to the circuit comes from "Ignition 2" pink in the diagram
Current flow from coil is from ECU ground, through box switching transistor, to coil NEG and through coil, out coil + and back to battery through the pink "ign 2"
Box circuit is from ECU ground, out pin 1, through resistor from right to left lower section, out resistor and back to battery on pink
Other section is s from ECU ground, out pin 3 (blue) to top section of resistor, through top section from left to right, through bottom section from right to left, and back to battery on pink.
This is "properly described" as neg to pos electron flow
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