The Turbocharger Bible

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Several years ago I spent so much time plugging numbers into the formulas in that link that I finally wrote a spreadsheet to do the math for me.

Good stuff.
 
looking at a paxton super charger for a 71 340 Duster. Any thoughts on performance increase typically seen with one of these kits....and do any of you guys much smarter than i when it comes to cars, does the hood need modifictaions?

thanks all....merry christmas
 
How about some help with the some of the math.

T1 = 75
P1 = 14.7
P2 = 24.7

The formula will now look like this:
T2 = 535 (24.7 ÷ 14.7)0.283 = 620 °R
You then need to subtract 460 to get °F, so simply do this:
620 - 460 = 160 °F Ideal Outlet Temperature
This is a temperature rise of 85 °F

THIS-> T2 = 535 (24.7 ÷ 14.7)0.283 = 620 °R
Is what I'm confused about. aka the 0.283
Thanks
 
How about some help with the some of the math.



THIS-> T2 = 535 (24.7 ÷ 14.7)0.283 = 620 °R
Is what I'm confused about. aka the 0.283
Thanks

Well still can NOT do the math BUT
I found a spread sheet for the hole equation!!!!!
[ame="http://dairally.net/daihard/chas/ZeekTurbo/Calc.xls"]Excel File Here[/ame]

This makes life much easier!:cheers:
 
How about some help with the some of the math.



THIS-> T2 = 535 (24.7 ÷ 14.7)0.283 = 620 °R
Is what I'm confused about. aka the 0.283
Thanks

Don't know how many people read this still, but the .283 is a constant, like 9.8 m/s^2 or 32.2 ft/s^2 for gravity.
 
So, what turbo do I need for my 360? LMAO!

Most people would do fine with a single 62mm or 66mm turbo from BorgWarner. They're only a few hundred more off the shelf than the China junk, and import guys push em to 500+rwhp (62mm) or 600+rwhp (66). Even a 57mm as a single will make 450rwhp maxed out.
 
Just found this awesome Turbo link but always a day late and a dollar short (actually $15 now...Ha).

Seriously wanting to add a turbo/O's to my 65' fish and SA Design book on Turbo's ordered from Summit should be on the porch tonight. Hope its a good read.
 
How about some help with the some of the math.



THIS-> T2 = 535 (24.7 ÷ 14.7)0.283 = 620 °R
Is what I'm confused about. aka the 0.283
Thanks


I have to agree, I am quite perplexed. The order of operations, workout the brackets first = 1.68. I am pretty sure in school I was told that if there is no operation between numbers and brackets (between the 535 and the bracket and between the bracket and the 0.283) then it is multiplied!so I get this: 535 x 1.68 x 0.283 = 254.3604.

help anyone?
 
I have to agree, I am quite perplexed. The order of operations, workout the brackets first = 1.68. I am pretty sure in school I was told that if there is no operation between numbers and brackets (between the 535 and the bracket and between the bracket and the 0.283) then it is multiplied!so I get this: 535 x 1.68 x 0.283 = 254.3604.

help anyone?

The 0.283 is an exponent. Take the pressure ratio and multiply it by itself 0.283 times. Then multiply the absolute inlet temp.
 
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