Help! I'm trying to understand why critical power for my ignition system goes through the printed circuit board on the back of my instrument cluster. Again this is a 1970 Dart with a standard cluster. I'm not talking about the ammeter gauge which I bypassed to an independent ammeter gauge under the dash long ago. I have been trying to chase an ignition based problem that can be resolved by pushing around the wiring under the dash. To help figure it out, I took out the seats, dropped the steering column and took the instrument panel loose so I could hook up the panel without it being in place. I discovered that with the car running, if I disconnected the 5 wire plug on the side of the instrument panel toward the center of the dash, the engine would die, plug it back in and the car starts fine, pull the plug and it dies. That seemed odd. What about the fuel gauge, temp gauge, oil light and dash lights (the only electrical items in the cluster) would cause power to the ignition to be lost????
Spending some time with my Chrysler service manual I found that the center wire on the three wire part of the Plug (as opposed to the two wire part), labelled G5-18dbl (18gauge dark blue wire) runs to a splice* and then wire J2A-16dbl goes to the bulkhead connector at position N. Go to the engine compartment diagram and and you see that wire then lead to something ominously labelled "NUMBER ONE SPLICE" with wires leading to the ballast resistor (J2A), the voltage regulator (I)(J2C), and one of the fields on the alternator (J2D). This is clearly seems to be why the ignition shuts off when you pull the plug... the question is what is the reason for this to go to the printed circuit board on the instrument panel. The one missing diagram in the manual is for the circuit board itself. Looking at the back of the circuit board it seems that this connects the oil pressure light to Bulkhead connector position K which leads only to the oil pressure sending unit screwed into the block.
*The other wires from the splice where G5 and J2A run to the brake warning light, to one of the wires in a connector leading to the ignition switch in the steering column and when traced goes to the gear selector indicator lamp, and to a key-in-ignition buzzer.
Is it really possible that this is wired so that if low oil pressure triggers the light that it shuts off the engine?!?!?!
Again HELP!!!
Spending some time with my Chrysler service manual I found that the center wire on the three wire part of the Plug (as opposed to the two wire part), labelled G5-18dbl (18gauge dark blue wire) runs to a splice* and then wire J2A-16dbl goes to the bulkhead connector at position N. Go to the engine compartment diagram and and you see that wire then lead to something ominously labelled "NUMBER ONE SPLICE" with wires leading to the ballast resistor (J2A), the voltage regulator (I)(J2C), and one of the fields on the alternator (J2D). This is clearly seems to be why the ignition shuts off when you pull the plug... the question is what is the reason for this to go to the printed circuit board on the instrument panel. The one missing diagram in the manual is for the circuit board itself. Looking at the back of the circuit board it seems that this connects the oil pressure light to Bulkhead connector position K which leads only to the oil pressure sending unit screwed into the block.
*The other wires from the splice where G5 and J2A run to the brake warning light, to one of the wires in a connector leading to the ignition switch in the steering column and when traced goes to the gear selector indicator lamp, and to a key-in-ignition buzzer.
Is it really possible that this is wired so that if low oil pressure triggers the light that it shuts off the engine?!?!?!
Again HELP!!!















